C++ functions declaration with macros

Question

I am asking about a way to improve code readability

I was able to make a macro like this for a small library I'm making

#define fun(name, arg1, arg2) void name(int arg1, int arg2)

NOTE: int is an existent class, but I replace it with int so anyone can run it

This would allow me to use this code to create a function:

fun(testFunction, x, y) {
  // do stuff
  std::cout << x << y << std::endl;
}

and then in my main:

int main() {

  testFunction(1, 2);

  return 0;
}

This works great (at least in Visual Studio, haven't tested in GCC but I think it works there too).

Is it possible to make a macro that would be like:

#define fun name(arg1, arg2)     void name(int arg1, int arg2)

so a macro that would allow me to declare a function like:

fun testFunction(x, y) {
  // do stuff
}

The actual thing I am asking if is there a way to make a macro that allows me to do this (for example)

CustomClassTemplate doStuff(CustomClass& arg1, CustomClassTemplate arg2, Library::Binary::Binary bin) {

  // do stuff

  return CustomClassTemplate(/*blah, blah, blah*/);

}

to this:

fun doStuff(arg1, arg2, bin) {
  // do stuff

  return CustomClassTemplate(/* blah blah blah*/);
}

you can create an empty class for each argument