'C# decimal take ceiling 2

I want to round my decimal value like 2.2222 to 2.23. When I use round,

decimal a = Math.Round((decimal)2.222, 2);

When I use ceiling, it cause 3

decimal c = Math.Ceiling((decimal)2.22);

How can I get 2.2222 to 2.23 ?

c++sharpmath


Solution 1:[1]

public static decimal CeilingAfterPoint(this decimal number, int digitsAfterPoint) {
    return Math.Ceiling(number * (decimal)Math.Pow(10, digitsAfterPoint))
           / (decimal)Math.Pow(10, digitsAfterPoint);
}

Solution 2:[2]

decimal c = Math.Ceiling((decimal)2.2222*100)/100;

but it's stupid.

Solution 3:[3]

try something like 

decimal c = Math.Ceiling((decimal)2.222*100)/100;

but it fails if your value is 2.22

Solution 4:[4]

Legacy question. But it deserves a right answer. Since .net core 3 you have been able to round decimals the following way:

Decimal.Round(2.222m, 2, MidpointRounding.ToPositiveInfinity);

It rounds upwards for the 2nd decimal.

MidpointRounding Docs

Sources

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Source: Stack Overflow

Solution Source
Solution 1
Solution 2 linkerro
Solution 3 dotNETbeginner
Solution 4 Kent Kostelac

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