awk - regex to print first matching group

Question

I am trying to get the first matching group based on regex, but its not printing anything after the second awk command. Not sure what I was doing wrong. Any help is greatly appreciated.

git status | awk 'NR=1' --> Limiting this to print first line.
On branch TA1692959

git status | awk 'NR=1' | awk '/^On\sbranch\s([\w]*)/{ print $1 }' --> I was trying to get the first word "TA1692959" after "On branch"this prints nothing.

Answer 1

git status |

{n,m,g}awk 'NR<--NF' FS='^On branch |[^[:alnum:]_].+$' OFS=

TA1241521

Answer 2

If you find yourself passing the data through multiple awk calls then chances are pretty good you can do the same thing with a single awk call, eg:

git status | awk 'NR==1 && /^On branch / {print $3; exit}'
TA1692959

In this case:

• there's no need for a regex; otherwise OP should update the question with additional samples showing the need for a regex
• the exit is optional and merely allows awk to skip processing the rest of the input stream