awk command with regex expression from variable fails

Question

I am trying to fetch elements from array on the basis specific pattern for example: alllist is array contains following data:

echo "${alllist[@]}":
setup-demo1-release-0 setup-demo1-release-1 setup-demo1-release-2 setup-demo1-production-0 setup-demo1-production-1

where type is a variable and can have values like -release-0 and -production-0 ending with hyphen and numeric number

setup-demo1 is same for all elements in array and <-release-0> and <-production-0> so created a regex expression in which it will look for something like this: for type=release it shall return all values

setup-demo1-release-0 setup-demo1-release-1

for type=production it shall return all values

setup-demo1-production-0 setup-demo1-production-1

Note: setup-demo1 can also be written as setup-release1 or setup-production1 so using grep for these words shall be ignored.

I have also tried achieving this through awk command:

endWithDigitPattern='[-0-9]'
targetNodes=($(echo "$alllist"| sed 's/[][",]//g' | tr ' ' '\n' | awk -v nTypes="release""$endWithDigitPattern" '$1~ nTypes {print $1}'))

and it is not returning expected result while executed through script file. and may be I am not using endWithDigitPattern variable in right way.

Let me know what's wrong with my command used.