Append for-loop output to a single array

Question

Given that print((sum(int(record[-1]) for record in groupOfRecords))) outputs:

0
0
0
2
10
0
0
0
0
2
10
0
0
0
0
6
0
0

After appending each int output to an empty array groups:

groups.append((sum(int(record[-1]) for record in groupOfRecords)))

print(groups) outputs the following:

[0]
[0, 0]
[0, 0, 0]
[0, 0, 0, 2]
[0, 0, 0, 2, 10]
[0, 0, 0, 2, 10, 0]
[0, 0, 0, 2, 10, 0, 0]
[0, 0, 0, 2, 10, 0, 0, 0]
[0, 0, 0, 2, 10, 0, 0, 0, 0]
[0, 0, 0, 2, 10, 0, 0, 0, 0, 2]
[0, 0, 0, 2, 10, 0, 0, 0, 0, 2, 10]
[0, 0, 0, 2, 10, 0, 0, 0, 0, 2, 10, 0]
[0, 0, 0, 2, 10, 0, 0, 0, 0, 2, 10, 0, 0]
[0, 0, 0, 2, 10, 0, 0, 0, 0, 2, 10, 0, 0, 0]
[0, 0, 0, 2, 10, 0, 0, 0, 0, 2, 10, 0, 0, 0, 0]
[0, 0, 0, 2, 10, 0, 0, 0, 0, 2, 10, 0, 0, 0, 0, 6]
[0, 0, 0, 2, 10, 0, 0, 0, 0, 2, 10, 0, 0, 0, 0, 6, 0]
[0, 0, 0, 2, 10, 0, 0, 0, 0, 2, 10, 0, 0, 0, 0, 6, 0, 0]

Whereas the desired result is simply the last array: [0, 0, 0, 2, 10, 0, 0, 0, 0, 2, 10, 0, 0, 0, 0, 6, 0, 0] in order for print(sum(groups)) to output 30