'add commas using String.Format for number and

Using String.Format how can i ensure all numbers have commas after every 3 digits eg 23000 = "23,000" and that 0 returns "0".

String.Format("{0:n}", 0); //gives 0.00 which i dont want. I dont want any decimal places, all numbers will be integers.

c++sharp


Solution 1:[1]

If your current culture seting uses commas as thousands separator, you can just format it as a number with zero decimals:

String.Format("{0:N0}", 0)

Or:

0.ToString("N0")

Solution 2:[2]

from msdn

double value = 1234567890;
Console.WriteLine(value.ToString("#,#", CultureInfo.InvariantCulture));

Displays 1,234,567,890

Solution 3:[3]

You can also play around a little with the CultureInfo object, if none of the other solutions work well for you:

        var x = CultureInfo.CurrentCulture;
        x.NumberFormat.NumberDecimalSeparator = ",";
        x.NumberFormat.NumberDecimalDigits = 0;
        x.NumberFormat.NumberGroupSizes = new int[] {3};

Solution 4:[4]

You can put a number after the N to specify number of decimal digits:

String.Format("{0:n0}", 0) // gives 0

Solution 5:[5]

I up-marked another answer and then found that zero values are an empty string. 

        System.Globalization.CultureInfo ci = new System.Globalization.CultureInfo("de-DE");
        System.Threading.Thread.CurrentThread.CurrentCulture = ci;

        double x = 23232323.21;
        string y = x.ToString("#,0", System.Globalization.CultureInfo.CurrentCulture);

The string is returned in the current culture which is German therefore y = 23.232.323

y = 0 when x = 0.

Solution 6:[6]

you just put it like this:

Console.WriteLine(**$**"Your current amount of money is: **{yourVar:c}**");

Solution 7:[7]

relatively american number to ordinal.

using static System.Threading.Thread;

public static string NumberToOrdinal(int number, CultureInfo? culture = null)
{
    var numberString = number.ToString(
        format: "#,0",
        provider: culture ?? CurrentThread.CurrentCulture);
    // Examine the last 2 digits.
    var lastDigits = number % 100;
    // If the last digits are 11, 12, or 13, use th. Otherwise:
    if (lastDigits is >= 11 and <= 13) return $"{numberString}th";
    // Check the last digit.
    return (lastDigits % 10) switch
    {
        1 => $"{numberString}st",
        2 => $"{numberString}nd",
        3 => $"{numberString}rd",
        _ => $"{numberString}th",
    };
}

ps i never comment on these things because stack overflow won't let me and sometimes its not worth upstaging everyone with a new answer for a slight improvement. Screw stackoverflow. I've been here for years and still can't comment- which is why i still don't post.

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 Guffa
Solution 2 pierroz
Solution 3 Jhonny D. Cano -Leftware-
Solution 4 TheSean
Solution 5 27k1
Solution 6 davejal
Solution 7

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