'a bash script that remove duplicates

This works wrong script should delete only copies, but this script deletes all files

#!/bin/bash

DIR=$1

if [[ -z "$DIR" ]]; then
    echo "Error: files dir is undefined"
fi

files="$( find ${DIR} -type f )"

for file1 in $files; do 
    for file2 in $files; do
        if cmp -s "$file1" "$file2"; then
            rm $file2
        fi
    done
done
bashmacosscript


Solution 1:[1]

Found this on superuser:

#!/bin/bash
declare -A arr
shopt -s globstar

for file in **; do
  [[ -f "$file" ]] || continue
   
  read cksm _ < <(md5sum "$file")
  if ((arr[$cksm]++)); then 
    echo "rm $file"
  fi
done

Solution 2:[2]

I find answer:

#!/bin/bash

DIR=$1

if [[ -z "$DIR" ]]; then
    echo "Error: files dir is undefined"
fi

files="$( find ${DIR} -type f )"

for file1 in $files; do 
    for file2 in $files; do
        if cmp -s "$file1" "$file2"; then
            rm $file2
        fi
    done
done

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 GravoLan
Solution 2 Tyler2P

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