Writing Quickperm algorithm in Kotlin and having problem adding elements to a set

Question

I am new to Kotlin and tried to write the Quickperm algorithm in Kotlin as a practice. My codes basically work when I use print to check the values. But when I created a set result to add all the permutations, the set remains unchanged. I then created an array check and added that to the set and that worked. So I am rather perturbed as to why this doesn't work down the line after I swapped the elements. Another issue I face is I have no idea how to pass the set to my main function. What I really want is to return result at the end of the permute function. What type is it? Thanks for any help on this.

fun permute(arr: Array<Char>): Array<Char>{
  var n = arr.size
  var indices = IntArray(n+1){ i -> i}
  var elements = arr
  var result = mutableSetOf(elements)
  //val check = arrayOf('d','e','f')
  //result.add(check)
  var i = 1
  var j:Int
  while (i<n){
    indices[i] = indices[i] - 1
    if (i%2!=0){
      j = indices[i]
    } else {
      j = 0
    }
    elements[i] = elements[j].also { elements[j] = elements[i]}
    result.add(elements)
    i = 1
    while (indices[i]==0){
      indices[i] = i
      i+=1
    }
  }
  for (e in result){
    printArray(e)
  }
  return elements
}

fun printArray(array: Array<Char>) {
  array.forEach { print("$it ")}
  println()
}

fun main() {
  var A = arrayOf('a','b','c')
  printArray(permute(A))
}