Is there a way to ignore "TypeError - 0 positional arguments but 1 was given"? [duplicate]

Question

I understand why this is happening, because callback doesn't take any arguments, but I'm passing one in x. But is there a stop this error from happening? i'm making an event manager, and sometimes you don't always need the extra information that is passed through the parameters.

import time

callbacks = {
    "on_foo": []
}

def callback_register(name, callback, *args, **kwargs):
    def cb(*args, **kwargs):
        return callback(*args, **kwargs)
    callbacks[name].append(cb)

def callback_unregister(name):
    del callbacks[name]

def callback_exists(name):
    return name in callbacks

def callback_call(name, *args, **kwargs):
    for cb in callbacks[name]:
        cb(*args, **kwargs)

def foo():
    print("FOO!")
    called_at = time.time()
    callback_call("on_foo", called_at)

callback_register("on_foo", lambda x: print(f"foo was called at {x}"))

callback_register("on_foo", lambda: print(f"foo has been called!")) #errors 
# no need for the called_at variable since it's not being used in this callback

foo()

I have solved my answer and would like to post an answer.

Answer 1

Like a regular function in Python, which can take variable number of arguments using *args , you could add *args to lambda arguments.

callback = lambda *args: print(5)

Edit: This question was abruptly changed. So updated answer:

lambda *args: print(f"foo has been called!")