'Is it possible to follow a developer on Gitlab

Just moved to Gitlab and found some interesting people there.

It'd be great to be able to follow them like in Github. I can't really find an answer on search engines. And there is no button I can see on Gitlab.

Is this possible? Or I should make a suggestion to Gitlab.



Solution 1:[1]

It was supported before, but GitLab 15.0 (May 2022) further simplifies the process:

Follow or unfollow someone from the user popup

Before this release, you could only follow or unfollow a GitLab user from their user profile. It was difficult to know if you were following a specific user unless you viewed the user’s profile.

In this release, thanks to Kev’s contribution, you can quickly follow and unfollow users through the user popup, no matter where you are in your GitLab workflow: in notes, issues, and more.
This reduces the extra step of going to the user’s profile, and makes it easier to follow and unfollow other GitLab users.

https://about.gitlab.com/images/15_0/follow.png -- Follow or unfollow someone from the user popup

See Documentation and Issue.

Solution 2:[2]

You can use tf.keras.layers.concatenate to merge Tensorflow keras sequential model.

Sample code

from tensorflow.keras.layers import concatenate
from tensorflow.keras.models import Model, Sequential
from tensorflow.keras.layers import Dense, Input

sequential_model1_in = Input(shape=(28, 28, 1))
sequential_model1_out = Dense(64, input_dim=20, activation='relu', name='layer_1')(sequential_model1_in)
sequential_model1 = Model(sequential_model1_in, sequential_model1_out)

sequential_model2_in = Input(shape=(28, 28, 1))
sequential_model2_out = Dense(64, input_dim=20, activation='relu', name='layer_2')(sequential_model2_in)
sequential_model2 = Model(sequential_model2_in, sequential_model2_out)


concatenated = concatenate([sequential_model1_out, sequential_model2_out])
out = Dense(1, activation='softmax', name='output_layer')(concatenated)

merged_model = Model([sequential_model1_in, sequential_model2_in], out)

Take a look on Tensorflow Intro to Autoencoders

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 VonC
Solution 2 TFer