'How to implement justify()-method in Java
I am trying to make my own justify()-method that takes a string and an integer as input, and fils in spacing so that the string has the same length as the given integer. I have followed the answers to this question to do it.
I want my code to work somethinglike this:
Input = "hi hi hi" 20
Output = hi hi hi
My code looks like this:
//Add spaces to string until it is of desired length
static String justify(StringBuilder text, int width) {
String[] inputLS = text.toString().split(" "); //Split string into list of words
//Sum the length of the words
int sumOfWordLengths = 0;
for (String word : inputLS){ sumOfWordLengths += word.length(); }
int padding = width-sumOfWordLengths; //How much spacing we need
String lastWord = inputLS[inputLS.length - 1]; //Last word in list of strings
//Remove the last word
ArrayList<String> withoutLast = new ArrayList<>
(Arrays.asList(inputLS).subList(0, inputLS.length - 1));
StringBuilder result = new StringBuilder(); //Initialize StringBuilder
//Iterate over strings and add spacing (we do not add spacing to the last word)
while (padding > 0){
for(String word : withoutLast){
result.append(word).append(" ");
padding--;
}
}
result.append(lastWord); //Add the last word again
return result.toString();
}
public static void main(String[] args) {
// IO
Scanner scanner = new Scanner(System.in); //Initialize scanner
System.out.println("Please enter a string and an integer: "); //Ask for input from user
String line = scanner.nextLine(); //Get input-string from user
String[] strings = line.split(" "); //Split string at " " into list of strings
String text = strings[0]; //Get first element from list as string
int width = Integer.parseInt(strings[1]); //Get second element from list as an int
// Create a string with three times the input text with spaces between
StringBuilder forJustify = new StringBuilder();
for(int i=0; i<3; i++){ forJustify.append(text).append(" "); }
// Make sure the length of the string is less than the given int
if (text == null || text.length() > width) {
System.out.println(text);
throw new IllegalArgumentException("Whoops! Invalid input. Try again.");
}
System.out.println("Gave this as input:\t" + forJustify);
System.out.println("Justify:\t\t\t" + justify(forJustify, width));
}
Which gives me this output:
Please enter a string and an integer:
hi 20
Gave this as input: hi hi hi
Justify: hi hi hi hi hi hi hi hi hi hi hi hi hi hi hi
But I want this output:
Please enter a string and an integer:
hi 20
Gave this as input: hi hi hi
Justify: hi hi hi
I know that there's something wring with the while-loop, but I don't understand how to fix it. All help is appreciated!
Solution 1:[1]
I came up with this solution after using the answer above:
static String justify(StringBuilder text, int width) {
//Turn StringBuilder into an arraylist of strings
String[] words = text.toString().split(" ");
List<String> arraylist = Arrays.asList(words);
//Find the length of the words and length of the padding needed
int lengthOfWords = 3 * arraylist.get(0).length();
int pad = width - lengthOfWords;
//Add padding by using format on each word separately and then combine the strings and add last word
String result;
if (pad % 2 == 0){
String temp1 = String.format("%" + (-(pad / 2) - 2) + "s", words[0]);
String temp2 = String.format("%" + (-(pad / 2) - 2) + "s", words[0]);
result = temp1 + temp2 + words[0];
} else {
pad--;
String temp1 = String.format("%" + (-(pad / 2) - 2) + "s", words[0]);
String temp2 = String.format("%" + (-(pad / 2) - 2) + "s", words[0]);
result = temp1 + temp2 + words[0];
//Turn string into arraylist
ArrayList<Character> cs = new ArrayList<>();
for (char c : result.toCharArray()){ cs.add(c); }
//Add last whitespace between first and second word
int index = nextSpaceIndex(cs);
cs.add(index, ' ');
//Turn arraylist back to string
StringBuilder str = new StringBuilder();
for (Character c : cs) { str.append(c); }
result = str.toString();
}
return result;
}
Which gives me this output:
Please enter a string and an integer:
hi 20
Justified: |hi hi hi|
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Mampenda |
