'concatenation TypeError: sequence item 0: expected str instance, list found
i've got a problem with my script when i want to concatenate to an address the layer i want to change. So i use this Script:
import glob
import arcpy
import pathlib
import os
import re
print("ouverture des droits")
users = ['geom01', 'geom02']
targetPattern = r"C:\Users\**\AppData\Roaming\\Esri\ArcGISPro\Favorites\[email protected]"
target = glob.glob(targetPattern)
print(target)
filename = r'\test.geom06.part_voiture'
joiend = [target,filename]
for ready in joiend:
print(''.join([target,r'\test.geom06.part_voiture']))
print(ready)
couche_voiture = ready
for i in users:
arcpy.ChangePrivileges_management(couche_voiture, i, "GRANT", "AS_IS")
message = "privilege modifié pour " + i + "sur finess"
print(message)
but when i execute the script i've got this message:
"C:\Program Files\ArcGIS\Pro\bin\Python\envs\arcgispro-py3\python.exe" C:/Users//Documents/tian.py
ouverture des droits
Traceback (most recent call last):
File "C:/Users//Documents/tian.py", line 20, in <module>
print(''.join([target,r'\test.geom06.part_voiture']))
TypeError: sequence item 0: expected str instance, list found
['C:\\Users\\\\AppData\\Roaming\\Esri\\ArcGISPro\\Favorites\\[email protected]']
Process finished with exit code 1
do you know how i can resolve that?
Solution 1:[1]
target is a list so you need to use join on it too
import glob
import arcpy
import pathlib
import os
import re
print("ouverture des droits")
users = ['geom01', 'geom02']
targetPattern = r"C:\Users\**\AppData\Roaming\\Esri\ArcGISPro\Favorites\[email protected]"
target = glob.glob(targetPattern)
print(target)
filename = r'\test.geom06.part_voiture'
joiend = [target,filename]
for ready in joiend:
# JOIN TARGET
print(''.join(["\".join(target),r'\test.geom06.part_voiture']))
print(ready)
couche_voiture = ready
for i in users:
arcpy.ChangePrivileges_management(couche_voiture, i, "GRANT", "AS_IS")
message = "privilege modifié pour " + i + "sur finess"
print(message)
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | definitlynothash |
