'Compare column name with a row value and getting other row value
I have a dataframe like this:
request_created_at sponsor_tier is_active status cash_in 2019/10 ... 2021/07
0 2019/10 2019/10 2.0 True 1 8901.00 ...
1 2019/10 2019/10 2.0 True 2 7602.00 ...
I want to compare all my columns with date e.g "2019/10" with the values of my first column and check if status == 1 and if status == 1 I want to copy my cash in value into the columns "2019/10" rows
Solution 1:[1]
def check_status (row, data):
if (row.status == 1) & (row.request_created_at == data):
return row.total_cash_in
elif (row.status == 4) & (row.request_created_at == data):
return row.total_cash_in
elif (row.status == 7) & (row.request_created_at == data):
return row.total_cash_in
else:
return 0
and then
for data in array_datas:
df[data] = df.apply(lambda row: check_status(row,data), axis=1)
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | h1tom1 |
