'BeautifulSoup find() takes no keyword arguments error

from bs4 import BeautifulSoup
from selenium import webdriver
import time 
import sys


query_txt = input("크롤링할 내용 입력 :")


path = "C:\Temp\chromedriver_240\chromedriver.exe"
driver = webdriver.Chrome(path)
driver.get("https://www.naver.com")
time.sleep(2)

driver.find_element_by_id("query").send_keys(query_txt)
driver.find_element_by_id("search_btn").click()

driver.find_element_by_link_text("블로그 더보기").click()

full_html = driver.page_source


soup = BeautifulSoup(full_html, 'html.parser')
content_list = soup.find('ul', id='elThumbnailResultArea')
print(content_list)
content = content_list.find('a','sh_blog_title _sp_each_url _sp_each_title' ).get_text()
print(content)


for i in content_list:   
    con = i.find('a', class_='sh_blog_title _sp_each_url _sp_each_title').get_text()
    print(con)
    print('\n')

i typed this code with watching online learning but in loop it always error. con = i.find('a', class_='sh_blog_title _sp_each_url _sp_each_title').get_text() this line show error 'find() takes no keyword arguments'

Solution 1:^[1]

The problem is, you have to use .find_all() to get all <a> tags. .find() only returns one tag (if there's any):

import requests
from bs4 import BeautifulSoup


url = 'https://search.naver.com/search.naver?query=tree&where=post&sm=tab_nmr&nso='
full_html = requests.get(url).content

soup = BeautifulSoup(full_html, 'html.parser')
content_list = soup.find_all('a', class_='sh_blog_title _sp_each_url _sp_each_title' )
    
for i in content_list:
    print(i.text)
    print('\n')

Prints:

[2017/???? ??] Romantic Tree


???/Banyan Tree Club & Spa/Club Members Restaurant


2020-06-27 Joshua Tree National Park Camping(?????...


[????/D-102] ???? '????? - like a tree'


Book Club - Magic Tree House # 1 : Dinosaur Before Dark...


?? ??, ??? ?? ????(Joshua Tree National Park)


???? TEA TREE ??? ?? 3???


Number of Nodes in the Sub-Tree With the Same Label


??? 100? ?? Giant tree


[?? ?? ??] ??? ????? : ???? sea&tree

Solution 2:^[2]

use .find('a', attrs={"class": "<Class name>"}) instead. Reference: Beatifulsoup docs

Solution 3:^[3]

These two links will definitely help you.

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution	Source
Solution 1	Andrej Kesely
Solution 2	sqz
Solution 3	Swaroop Humane

'BeautifulSoup find() takes no keyword arguments error

Solution 1:[1]

Solution 2:[2]

Solution 3:[3]

Sources

Related Questions

Solution 1:^[1]

Solution 2:^[2]

Solution 3:^[3]